Consider the reaction CuSO_4 + KCN to CuCN + | vedclass

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(D) The reaction proceeds as follows: $1$. $2CuSO_4 + 4KCN 	o 2CuCN + (CN)_2 + 2K_2SO_4$. Here,$Y$ is $(CN)_2$ (cyanogen). $2$. Cyanogen $(CN)_2$ has

Vedclass · Accepted Answer

$Z$ is a diamagnetic complex with $sp^3$ hybridization.

Vedclass · Answer

(D) The reaction proceeds as follows: $1$. $2CuSO_4 + 4KCN 	o 2CuCN + (CN)_2 + 2K_2SO_4$. Here,$Y$ is $(CN)_2$ (cyanogen). $2$. Cyanogen $(CN)_2$ has a linear structure,not an open book-like structure. $3$. When $CuCN$ reacts with excess $KCN$,it forms the complex $K_3[Cu(CN)_4]$. $4$. In $K_3[Cu(CN)_4]$,the copper is in the $+1$ oxidation state $(Cu^+)$,which has a $d^{10}$ configuration. $5$. The complex $[Cu(CN)_4]^{3-}$ is tetrahedral with $sp^3$ hybridization. $6$. Since all $d$-orbitals are filled $(d^{10})$,there are no unpaired electrons,making it a diamagnetic complex. $7$. Therefore,statement $D$ is correct.

$LIST-I$	$LIST-II$
$P. dsp^2$	$1. [FeF_6]^{4-}$
$Q. sp^3$	$2. [Ti(H_2O)_3Cl_3]$
$R. sp^3d^2$	$3. [Cr(NH_3)_6]^{3+}$
$S. d^2sp^3$	$4. [FeCl_4]^{2-}$
	$5. Ni(CO)_4$
	$6. [Ni(CN)_4]^{2-}$

Consider the reaction $CuSO_4 + KCN \to CuCN + Y \xrightarrow{\text{excess } K^{+}CN^{-}} Z$. Identify the correct statement regarding the products $Y$ and $Z$.

Similar Questions

Explain the complex species $[Ni(CN)_4]^{2-}$ on the basis of Valence Bond Theory $(VBT)$.

Which of the following statements is correct?

The complex $[Pt(NH_3)_4]^{2+}$ has $.....$ structure.

Which of the following statements are correct?
$i$. $[Mn(CN)_6]^{3-}, [MnCl_6]^{3-}$ both are paramagnetic
$ii$. Both $[NiCl_4]^{2-}, [Ni(CO)_4]$ are tetrahedral and diamagnetic
$iii$. $[Co(NH_3)_6]^{3+}$ is an inner orbital complex,but $[Ni(NH_3)_6]^{2+}$ is an outer orbital complex

Match each set of hybrid orbitals from $LIST-I$ with complex(es) given in $LIST-II$. The correct option is

$LIST-I$ $LIST-II$

$P. dsp^2$ $1. [FeF_6]^{4-}$

$Q. sp^3$ $2. [Ti(H_2O)_3Cl_3]$

$R. sp^3d^2$ $3. [Cr(NH_3)_6]^{3+}$

$S. d^2sp^3$ $4. [FeCl_4]^{2-}$

$5. Ni(CO)_4$

$6. [Ni(CN)_4]^{2-}$

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